The New England Patriots are experiencing a strong season, sitting at the top of the AFC with an impressive 10-2 record as they head into Week 13. However, their position is not guaranteed, as other teams intensify their efforts to catch up during the remainder of the regular season.
Although the Patriots lead the AFC East division, their most significant rival is the Buffalo Bills. Despite some recent struggles, the Bills remain a formidable opponent in the league. As they look to bolster their offense ahead of crucial games, Buffalo has made a noteworthy move by signing former Patriots wide receiver Brandin Cooks.
Cooks, who was recently released by the New Orleans Saints, brings a wealth of experience and speed to the Bills’ lineup. After clearing waivers, he was officially signed to Buffalo’s active roster. The Bills announced this development on social media, emphasizing their commitment to enhancing their offensive capabilities.
The wide receiver had a standout season in 2017 with the Patriots, recording 65 receptions for 1,082 yards and seven touchdowns. Despite his speed and potential as a playmaker, Cooks struggled to find his place with the Saints this season, managing only 19 catches for 165 yards, which led him to request his release.
With the Bills in need of offensive reinforcements, Cooks is expected to get immediate playing time. Notably, he will have the opportunity to face his former team when New England and Buffalo meet again in Week 15, adding an extra layer of excitement to the upcoming matchup.
This signing reflects the competitive nature of the AFC and highlights the ongoing efforts by teams to make strategic improvements as the season progresses. Fans can look forward to seeing how Cooks fits into the Bills’ offensive scheme and whether he can help lead them back into contention.